sorted()<\/a> function that returns a sorted list of an iterable object. It sorts string values alphabetically and numbers numerically. It also allows you to mention the sort key or specify a formula for it. Here is an example to sort a dict using its values.<\/p>\n\n\n\nd1={k: v for k, v in sorted(data.items(), key=lambda item: item[1])}
print(d1)<\/pre>\n\n\n\nIn the above code, we call sorted() function on output of data.items(). data.items() returns a list of tuples where each tuple has a key-value pair. We also specify the key to be the 2nd item in each tuple, that is, the value, and not the key. For this, we use lambda function. The sorted() function returns a list of tuples, that have been sorted by the 2nd item in each tuple. <\/p>\n\n\n\n
We use a list comprehension to create key-value pairs out of each tuple and store each of them in a new dictionary.<\/p>\n\n\n\n
Here is the output.<\/p>\n\n\n\n
{'a': 1, 'c': 2, 'b': 3}<\/pre>\n\n\n\nAlternatively, you can call the dict() function to convert the result of sorted() function into dict.<\/p>\n\n\n\n
d1=dict(sorted(data.items(), key=lambda item: item[1]))
print(d1) # output is {'a': 1, 'c': 2, 'b': 3}<\/pre>\n\n\n\nIf you want to reverse sort the dictionary, then mention reverse=True argument in sorted function.<\/p>\n\n\n\n